2x+10x^2=36

Solution for 2x+10x^2=36 equation:

2x+10x^2=36

We move all terms to the left:

2x+10x^2-(36)=0

a = 10; b = 2; c = -36;
Δ = b2-4ac
Δ = 22-4·10·(-36)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-38}{2*10}=\frac{-40}{20}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+38}{2*10}=\frac{36}{20}
=1+4/5
$